Home
Class 12
MATHS
If veca,vecb and vecc are three mutually...

If `veca,vecb and vecc` are three mutually perpendicular vectors, then the vector which is equally inclined to these vectors is

Promotional Banner

Similar Questions

Explore conceptually related problems

If veca,vecb,vecc are three mutually perpendicular vectors, then the vector which is equally inclined to these vectors is (A) veca+vecb+vecc (B) veca/|veca|+vecb/|vecb|+vec/|vecc| (C) veca/|veca|^2+vecb/|vecb|^2+vecc/|vecc|^2 (D) |veca|veca-|vecb|vecb+|vecc|vecc

If veca,vecb and vecc are three mutually perpendicular unit vectors and vecd is a unit vector which makes equal angle with veca,vecb and vecc , then find the value of |veca+vecb+vecc+vecd|^(2) .

If veca,vecb,vecc are mutually perpendicular vectors of equal magnitude show that veca+vecb+vecc is equally inclined to veca, vecb and vecc

if veca, vecb and vecc are there mutually perpendicular unit vectors and veca ia a unit vector then find the value of |2veca+ vecb + vecc |^2

veca and vecb are two unit vectors that are mutually perpendicular. A unit vector that if equally inclined to veca, vecb and veca xxvecb is equal to

If veca , vecb , vecc are three mutually perpendicular unit vectors, then prove that ∣ ​ veca + vecb + vecc | ​ = sqrt3 ​

Statement 1: veca, vecb and vecc arwe three mutually perpendicular unit vectors and vecd is a vector such that veca, vecb, vecc and vecd are non- coplanar. If [vecd vecb vecc] = [vecdvecavecb] = [vecdvecc veca] = 1, " then " vecd= veca+vecb+vecc Statement 2: [vecd vecb vecc] = [vecd veca vecb] = [vecdveccveca] Rightarrow vecd is equally inclined to veca, vecb and vecc .

If veca,vecb and vecc are three non-coplanar vectors then the length of projection of vector veca in the plane of the vectors vecb and vecc may be given by

if veca,vecb and vecc are mutally perpendicular vectors of equal magnitudes, then find the angle between vectors and veca+ vecb+vecc .

If veca,vecb and vecc are three mutually perpendicular unit vectors then (vecr.veca)veca+(vecr.vecb)vecb+(vecr.vecc)vecc= (A) ([veca vecb vecc]vecr)/2 (B) vecr (C) 2[veca vecb vecc] (D) none of these