If `veca .vecb =beta and veca xx vecb = vecc ," then " vecb` is

if veca xx vecb = vecc ,vecb xx vecc = veca , " where " vecc ne vec0 then (a) |veca|= |vecc| (b) |veca|= |vecb| (c) |vecb|=1 (d) |veca|=|vecb|= |vecc|=1

given that veca. vecb = veca.vecc, veca xx vecb= veca xx vecc and veca is not a zero vector. Show that vecb=vecc .

If veca, vecb, vecc and vecd ar distinct vectors such that veca xx vecc = vecb xx vecd and veca xx vecb = vecc xx vecd . Prove that (veca-vecd).(vecc-vecb)ne 0, i.e., veca.vecb + vecd.vecc nevecd.vecb + veca.vecc.

Let veca and vecb are vectors such that |veca|=2, |vecb|=3 and veca. vecb=4 . If vecc=(3veca xx vecb)-4vecb , then |vecc| is equal to

veca,vecb,vecc are three non-coplanar such that veca + vecb + vecc = alpha vecd and vecb + vecc + vecd = beta veca , then veca + vecb + vecc + vecd is equal to:

Let veca = hati + hatj +hatjk, vecc =hatj - hatk and a vector vecb be such that veca xx vecb = vecc and veca.vecb=3 . Then |vecb| equals:

If veca + 2 vecb + 3 vecc = vec0 " then " veca xx vecb + vecb xx vecc + vecc xx veca=

If |veca|=3, |vecb|=1, |vecc|=4 and veca + vecb + vecc= vec0 , find the value of veca.vecb+ vecb.vecc + vecc.veca .

If |veca|=4, |vecb|=4 and |vecc|=5 such that veca bot vecb + vecc, vecb bot (vecc + veca) and vecc bot (veca + vecb) , then |veca + vecb + vecc| is:

If [veca xx vecb vecb xx vecc vecc xx veca]=lambda[veca vecb vecc]^2 , then lambda is equal to