If `veca, vecb and vecc ` are , mutually perpendicular vcetors and `veca=alpha(vecaxxvecb)+beta(vecbxxvecc)+gamma(veccxxveca)and [vecavecbvecc] =1` , then find the value of `alpha +beta +gamma`

If veca,vecb,vecc are mutually perpendicular vector and veca=alpha(vecaxxvecb)+beta(vecbxxvecc)+gamma(veccxxveca) and [veca vecb vecc]=1 then vecalpha+vecbeta+vecgamma= (A) |veca|^2 (B) -|veca|^2 (C) 0 (D) none of these

If vec(alpha)=x(vecaxxvecb)+y(vecbxxvecc)+z(veccxxveca) and [veca vecb vecc]=1/8 , then x+y+z=

If alpha(veca xx vecb)+beta(vecb xx vecc)+lambda(vecc xx veca)=0 , then

If vecr=x(vecaxxvecb)+y(vecbxxvecc)+z(veccxxveca) and [veca vecb vecc]=(1)/(3) , then x+y+z is equal to

Prove that (vecbxxvecc)xx(veccxxveca)=[veca vecb vecc]vecc

Prove that (vecbxxvecc)xx(veccxxveca)=[veca vecb vecc]vecc

If (vecaxxvecb).[(vecbxxvecc)xx(veccxxveca)]=(veca.(vecbxxvecc))^(k) find k .

if veca, vecb and vecc are there mutually perpendicular unit vectors and veca ia a unit vector then find the value of |2veca+ vecb + vecc |^2

If vecaxx(vecaxxvecb)=vecbxx(vecbxxvecc) and veca.vecb!=0 , then [(veca,vecb,vecc)]=

For three vectors veca+vecb+vecc=0 , check if (vecaxxvecb)=(vecbxxvecc)=(veccxxveca)