A parallelogram is construted on `3veca + vecb and veca- 4vecb`, where `|veca|=6 and |vecb|=8 and veca and vecb` are anti-parallel . Then the length of the longer diagonal is

A parallelogram is constructed on 3veca+vecb and veca-4vecb, where |veca|=6 and |vecb|=8 and veca and vecb are anti parallel then the length of the longer diagonal is (A) 40 (B) 64 (C) 32 (D) 48

A parallelogram is constructed on 3veca+vecb and veca-4vecb, where |veca|=6 and |vecb|=8 and veca and vecb are anti parallel then the length of the longer diagonal is (A) 40 (B) 64 (C) 32 (D) 48

If veca * vecb = |veca xx vecb| , then this angle between veca and vecb is,

If | veca + vecb|=| veca - vecb| , then what is the angle between veca and vecb ?

If |veca|=5 , |veca-vecb| = 8 and |veca +vecb|=10 then find |vecb|

If |veca|=8,|vecb| = 3 and |veca xxvecb|=12 , find veca.vecb

The value of [(veca-vecb, vecb-vecc, vecc-veca)] , where |veca|=1, |vecb|=5, |vecc|=3 , is

If veca and vecb are non - zero vectors such that |veca + vecb| = |veca - 2vecb| then

If |veca - vecb|=|veca| =|vecb|=1 , then the angle between veca and vecb , is

Find |veca| and |vecb| if (veca+vecb).(veca-vecb)=8 and |veca|=8|vecb| .