If non-zero vectors `veca and vecb` are perpendicular to each other, then the solution of the equation `vecr × veca = vecb` is given by

If vecA + vecB = vecR and 2vecA + vecB s perpendicular to vecB then

If the vectors veca and vecb are perpendicular to each other then a vector vecv in terms of veca and vecb satisfying the equations vecv.veca=0, vecv.vecb=1 and [(vecv, veca, vecb)]=1 is

Let veca and vecb be two non- zero perpendicular vectors. A vector vecr satisfying the equation vecr xx vecb = veca can be

If veca and vecb are two unit vectors such that veca+2vecb and 5veca-4vecb are perpendicular to each other, then the angle between veca and vecb is

If vecb is not perpendicular to vecc . Then find the vector vecr satisfying the equation vecr xx vecb = veca xx vecb and vecr. vecc=0

If vecb is not perpendicular to vecc . Then find the vector vecr satisfying the equation vecr xx vecb = veca xx vecb and vecr. vecc=0

If veca and vecb are unit vectors such that 2veca-4vecb and 10veca+8vecb are perpendicular to each other, then find the angle between these two vectors.

The vector (veca.vecb)vecc-(veca.vecc)vecb is perpendicular to

If veca an vecb are perpendicular vectors, |veca+vecb|=13 and |veca|=5 , find the value of |vecb| .

Let veca and vecb be unit vectors that are perpendicular to each other l. then [veca+ (veca xx vecb) vecb + (veca xx vecb) veca xx vecb] will always be equal to