The reflection of the point `veca` in the plane `vecr.vecn=q` is

The projection of point P(vecp) on the plane vecr.vecn=q is (vecs) , then

Distance of point P(vecP) from the plane vecr.vecn=0 is

The image (or reflection) of the point (1,2-1) in the plane vecr.(3hati-5hatj+4hatk)=5 is

Find the equation of a straight line in the plane vecr.vecn=d which is parallel to vecr.vecn=d("where "vecn.vecb=0) .

The equation of the line throgh the point veca parallel to the plane vecr.vecn =q and perpendicular to the line vecr=vecb+tvecc is (A) vecr=veca+lamda (vecnxxvecc) (B) (vecr-veca)xx(vecnxxvecc)=0 (C) vecr=vecb+lamda(vecnxxvecc) (D) none of these

Find the distance of the point veca from the plane vecr*hatn=d measured parallel to the line vecr=vecb+vec(tc) .

Find the projection of the line vecr=veca+tvecb on the plane given by vecr.vecn=q .

Write the coordinates of the point which is the reflection of the point (a,b,c) in the xz-plane.

The equation of the plane containing the line vecr= veca + k vecb and perpendicular to the plane vecr . vecn =q is :

The equation of the plane contaiing the lines vecr=veca_(1)+lamda vecb and vecr=veca_(2)+muvecb is