Find the value of a so that the volume of the parallelopiped formed by vectors `hati+ahatj+hatk,hatj+ahatkandahati+hatk` becomes minimum.

The value of a, such that the volume of the parallelopiped formed by the vectors hati+hatj+hatk, hatj+ahatk and ahati+hatk becomes minimum, is

The value of a so thast the volume of parallelpiped formed by vectors hati+ahatj+hatk, hatj+ahatk, ahati+hatk becomes minimum is (A) sqrt93) (B) 2 (C) 1/sqrt(3) (D) 3

If the volume of parallelopiped formed by the vectors hati+lamdahatj+hatk,hatj+lamdahatk and lamdahati+hatk is minimum then lamda is equal to (1) -(1)/(sqrt(3)) (2) (1)/(sqrt(3)) (3) sqrt(3) (4) -sqrt(3)

Find the volume of the parallelepiped with co-terminous edges 2 hati + hatj - hatk, hati + 2 hatj + 3 hatk and - 3 hati - hatj + hatk

Find the volume of the parallelopiped whose edges are represented by a=2hati-3hatj+4hatk,b=hati+2hatj-hatk and c=3hati-hatj+2hatk .

Find the volume of the parallelopiped, whose three coterminous edges are represented by the vectors hati+hatj+hatk,hati-hatj+hatk,hati+2hatj-hatk .

If the volume of the parallelopiped whose coterminus edges are represented by the vectors 5hati -4hatj +hatk , 4hati+3hatj-lambda hatk and hati-2hatj+7hatk is 216 cubic units, find the value of lambda .

Find the unit vector in the direction of the resultant of vectors hati-hatj+hat3k, 2hati+hatj-2hatk and 2hatj-2hatk

The angle between vectors (hati+hatj+hatk) and (hatj+hatk) is :

Find the value of lamda so that the two vectors 2hati+3hatj-hatk and -4hati-6hatj+lamda hatk are parallel