The position verctors of the points A and B with respect of O are `2hati+2hatj+hatk and 2hati+4hatj+4hatk`, the length of the internal bisector of `angleBOA` of `DeltaAOB` is

If the position vectors of A and B respectively hati+3hatj-7hatk and 5 hati-2hatj+4hatk , then find AB

The position vectors of the points A, B, C are 2 hati + hatj - hatk , 3 hati - 2 hatj + hatk and hati + 4hatj - 3 hatk respectively . These points

The position vectors of the points A, B, C are 2 hati + hatj - hatk , 3 hati - 2 hatj + hatk and hati + 4hatj - 3 hatk respectively . These points

The position vectors of the points A, B, C are 2 hati + hatj - hatk , 3 hati - 2 hatj + hatk and hati + 4hatj - 3 hatk respectively . These points

If a=2hati+2hatj-8hatk and b=hati+3hatj-4hatk , then the magnitude of a+b is equal to

If the sides of an angle are given by vectors veca=hati-2hatj+2hatk and vecb=2hati+hatj+2hatk , then find the internal bisector of the angle.

The position vectors of points A,B and C are hati+hatj,hati + 5hatj -hatk and 2hati + 3hatj + 5hatk , respectively the greatest angle of triangle ABC is

The position vectors of A and B are 2hati-9hatj-4hatk and 6hati-3hatj+8hatk respectively, then the magnitude of AB is

The position vectors of the vertices A,B and C of a triangle are hati-hatj-3hatk,2hati+hatj-2hatk and -5hati+2hatj-6hatk , respectively. The length of the bisector AD of the angleBAC , where D is on the segment BC, is

If the position vectors of the vertices of a triangle be 2hati+4hatj-hatk,4hati+5hatj+hatk and 3 hati+6hatj-3hatk , then the triangle is