`veca and vecb` are two non collinear vectors then `xveca+yvecb` (where x and y are scalars) represents a vector which is (A) parallel to `vecb` (B) parallel to `veca` (C) coplanar with `veca and vecb` (D) none of these

If veca and vecb are two non collinear vectors and vecu = veca-(veca.vecb).vecb and vecv=veca x vecb then vecv is

If veca and vecb are non - zero vectors such that |veca + vecb| = |veca - 2vecb| then

If veca and vecb are two non collinear unit vectors and |veca+vecb|=sqrt(3) then find the value of (veca-vecb).(2veca+vecb)

If vec a , vec ba n d vec c are three non coplanar vectors, then ( veca + vecb + vecc )[( veca + vecb )×( veca + vecc )] is :

Given that veca and vecb are two non zero vectors, then the value of (veca + vecb) xx (veca-vecb) is,

If veca and vecb be two non collinear vectors such that veca=vecc+vecd , where vecc is parallel to vecb and vecd is perpendicular to vecb obtain expression for vecc and vecd in terms of veca and vecb as: vecd= veca- ((veca.vecb)vecb)/b^2,vecc= ((veca.vecb)vecb)/b^2

If veca,vecb,vecc are any thre vectors then (vecaxxvecb)xxvecc is a vector (A) perpendicular to vecaxxvecb (B) coplanar with veca and vecb (C) parallel to vecc (D) parallel to either veca or vecb

Let veca and vecb be two non-collinear unit vectors. If vecu=veca-(veca.vecb)vecb and vecv=vecaxxvecb , then |vecv| is

If veca, vecb and vecc are three non-coplanar vectors, then (veca + vecb + vecc). [(veca + vecb) xx (veca + vecc)] equals

If veca and vecb are two unit vectors, then the vector (veca+vecb)xx(vecaxxvecb) is parallel to the vector