The perpendicular distance between the line `vecr = 2hati-2hatj+3hatk+lambda(hati-hatj+4hatk)` and the plane `vecr.(hati + 5hatj + hatk) = 5` is :

Angle between the line vecr=(2hati-hatj+hatk)+lamda(-hati+hatj+hatk) and the plane vecr.(3hati+2hatj-hatk)=4 is

Find the angle between the line vecr=(hati+2hatj-hatk)+lamda(hati-hatj+hatk) and the plane ver.(2hati-hatj+hatk)=4

Find the angle between the line vecr = (2hati+hatj-hatk)+lambda(2hati+2hatj+hatk) and the plane vecr.(6hati-3hatj+2hatk)+1=0 .

The angle between the line vecr = ( 5 hati - hatj - 4 hatk ) + lamda ( 2 hati - hatj + hatk) and the plane vec r.( 3 hati - 4 hatj - hatk) + 5=0 is

The line vecr = 2hati - 3 hatj - hatk + lamda ( hati - hatj + 2 hatk ) lies in the plane vecr. (3 hati + hatj - hatk) + 2=0 or not

Find the points of intersection of the line vecr = (2hati - hatj + 2hatk) + lambda(3hati + 4hatj + 2hatk) and the plane vecr.(hati - hatj + hatk) = 5

Find the distance of the point (-1,-5,-10) from the point of the intersection of the line vecr = 2hati-2hatk+lambda(3hati+4hatj+2hatk) and the plane vecr.(hati-hatj+hatk) = 5 .

If the point of intersection of the line vecr = (hati + 2 hatj + 3 hatk ) + lambda( 2 hati + hatj+ 2hatk ) and the plane vecr (2 hati - 6 hatj + 3 hatk) + 5=0 lies on the plane vec r ( hati + 75 hatj + 60 hatk) -alpha =0, then 19 alpha + 17 is equal to :

Find the shortest distance between the lines vecr = 2hati - hatj + hatk + lambda(3hati - 2hatj + 5hatk), vecr = 3hati + 2hatj - 4hatk + mu(4hati - hatj + 3hatk)

Shortest distance between the lines: vecr=(4hati-hatj)+lambda(hati+2hatj-3hatk) and vecr=(hati-hatj+2hatk)+u(2hati+4hatj-5hatk)