If `vecV=x(vecaxxvecb)+y(vecbxxvecc)+z(veccxxveca) and vecV.(veca+vecb+vecc)=x+y+z.` The valueof `[veca vecb vecc] if x+y+z!=0` ils (A) 0 (B) 1 (C) -1 (D) 2

If vec(alpha)=x(vecaxxvecb)+y(vecbxxvecc)+z(veccxxveca) and [veca vecb vecc]=1/8 , then x+y+z=

If vecr=x(vecaxxvecb)+y(vecbxxvecc)+z(veccxxveca) Such that x+y+z!=0 and vecr.(veca+vecb+vecc)=x+y+z , then [veca vecb vecc]=

If vecr=x(vecaxxvecb)+y(vecbxxvecc)+z(veccxxveca) and [veca vecb vecc]=(1)/(3) , then x+y+z is equal to

If vecaxx(vecaxxvecb)=vecbxx(vecbxxvecc) and veca.vecb!=0 , then [(veca,vecb,vecc)]=

Express veca,vecb,vecc in terms of vecbxxvecc, veccxxveca and vecaxxvecb .

If veca,vecb,vecc are mutually perpendicular vector and veca=alpha(vecaxxvecb)+beta(vecbxxvecc)+gamma(veccxxveca) and [veca vecb vecc]=1 then vecalpha+vecbeta+vecgamma= (A) |veca|^2 (B) -|veca|^2 (C) 0 (D) none of these

If vecA=(vecbxxvecc)/([vecb vecc veca]), vecB=(veccxxveca)/([vecc veca vecb]), vecC=(vecaxxvecb)/([veca vecb vecc]) find [vecA vecB vecC]

If veca+2vecb+3vecc=0 , then vecaxxvecb+vecbxxvecc+veccxxveca=

If vecaxxvecb=vecc,vecb xx vecc=veca, where vecc != vec0, then

If [vecaxxvecb vecbxxvecc veccxxveca]=lamda [veca vecb vecc]^2 then lamda is equal to (A) 1 (B) 2 (C) 3 (D) 0