If `veca,vecb,vecc,vecd` are any for vectors then `(vecaxxvecb)xx(veccxxvecd)` is a vector (A) perpendicular to `veca,vecb,vecc,vecd` (B) along the the line intersection of two planes, one containing `veca,vecb and ` the other containing `vecc,vecd`. (C) equally inclined both `vecaxxvecb and veccxxvecd` (D) none of these

If the vectors veca, vecb, vecc and vecd are coplanar vectors, then (vecaxxvecb)xx(veccxxvecd) is equal to

If the vectors veca, vecb, vecc, vecd are coplanar show that (vecaxxvecb)xx(veccxxvecd)=vec0

If veca,vecb,vecc and vecd are unit vectors such that (vecaxxvecb)*(veccxxvecd)=1 and veca.vecc=1/2, then

If veca,vecb,vecc are any thre vectors then (vecaxxvecb)xxvecc is a vector (A) perpendicular to vecaxxvecb (B) coplanar with veca and vecb (C) parallel to vecc (D) parallel to either veca or vecb

If veca, vecb, vecc are any three non coplanar vectors, then (veca+vecb+vecc).(vecb+vecc)xx(vecc+veca)

If veca, vecb, vecc are any three non coplanar vectors, then [(veca+vecb+vecc, veca-vecc, veca-vecb)] is equal to

For any four vectors, prove that ( veca × vecb )×( vecc × vecd )=[ veca vecc vecd ] vecb −[ vecb vecc vecd ] veca

For any three vectors veca,vecb,vecc their product would be a vector if one cross product is folowed by other cross product i.e (vecaxxvecb)xxvecc or (vecbxxvecc)xxveca etc. For any four vectors veca,vecb,vecc,vecd the product would be a vector with the help of sequential cross product or by cross product of two vectors obtained by corss product of two pair i.e. (vecaxx(vecbxxvecc))xxvecd or (vecaxxvecb)xx(veccxxvecd). Now answer the following question: (vecaxxvecb)x(veccxxvecd) would be a (A) equally inclined with veca,vecb,vecc,vecd (B) perpendicular with (vecaxxvecb)xxvecc and vecc (C) equally inclined with vecaxxvecb and veccxxvecd (D) none of these

If veca, vecb, vecc are any three vectors such that (veca+vecb).vecc=(veca-vecb)vecc=0 then (vecaxxvecb)xxvecc is

If veca,vecb and vecc are non coplaner vectors such that vecbxxvecc=veca , veccxxveca=vecb and vecaxxvecb=vecc then |veca+vecb+vecc| =