If `(vecaxxvecb)xxvecc=vecax(vecbxxvecc)` then (A) `(veccxxveca)xxvecb=0` (B) `vecbxx(veccxxveca)=0` (C) `veccxx(vecaxxvecb)=0` (D) none of these

Prove that vecaxx(vecbxxvecc)+vecbxx(veccxxveca)+veccxx(vecaxxvecb)=vec0

For vectors veca,vecb,vecc,vecd, vecaxx(vecbxxvecc)=(veca.vecc)vecb-(veca.vecb)vecc and (vecaxxvecb).(veccxxvecd)=(veca.vecc)(vecb.vecd)-(veca.vecd)(vecb.vecc) Now answer the following question: (vecaxxvecb).(veccxxvecd) is equal to (A) veca.(vecbxx(veccxxvecd)) (B) |veca|(vecb.(veccxxvecd)) (C) |vecaxxvecb|.|veccxxvecd| (D) none of these

Prove that vecaxx(vecb+vecc)+vecbxx(vecc+veca)+veccxx(veca+vecb)=0

For vectors veca,vecb,vecc,vecd, vecaxx(vecbxxvecc)=(veca.vecc)vecb-(veca.vecb)vecc and (vecaxxvecb).(veccxxvecd)=(veca.vecc)(vecb.vecd)-(veca.vecd)(vecb.vecc) Now answer the following question: {(vecaxxvecb).xxvecc}.vecd would be equal to (A) veca.(vecbxx(veccxxvecd)) (B) ((vecaxxvecc)xxvecb).vecd (C) (vecaxxvecb).(veccxxvecd) (D) none of these

If veca,vecb,vecc be non coplanar vectors and vecp=(vecbxxvecc)/([veca vecb vecc]) , vecq=(veccxxveca)/([veca vecb vecc]) , vecr=(vecaxxvecb)/([veca vecb vecc]) then (A) vecp.veca=1 (B) vecp.veca+vecq.vecb+vecr.vecc=3 (C) vecp.veca+vecq.vecb+vecr.vecc=0 (D) none of these

If veca+2vecb+3vecc=0 , then vecaxxvecb+vecbxxvecc+veccxxveca=

If vecaxx(vecbxxvecc)=vecbxx(veccxxveca) and [(vec, vecb, vecc)]!=0 then vecaxx(vecbxxvecc) is equal to

For any three vectors veca, vecb, vecc the value of vecaxx(vecbxxvecc)+vecbxx(veccxxveca)+veccxx(vecaxxvecb) , is

If vertices of /_\ABC are A(veca), B(vecb) and C(vecc) then length of perpendicular from C to AB is (A) (|vecbxxvecc+veccxxveca+vecaxxvecb|)/(|veca-vecb|) (B) (|vecbxxvecc+veccxxveca+vecaxxvecb|)/(|veca+vecb|) (C) (|vecbxxvecc|+|veccxxveca|+|vecaxxvecb|)/(|veca-vecb|) (D) none of these

If 4veca+5vecb+9vecc=0 " then " (vecaxxvecb)xx[(vecbxxvecc)xx(veccxxveca)] is equal to