If unit vectors `veca and vecb` are inclined at an angle `2 theta` such that `|veca - vecb| lt 1 and 0 le theta le pi`, then `theta` lies in the interval

If the unit vectors veca and vecb are inclined of an angle 2 theta such that |veca -vecb| lt 1 and 0 le theta le pi then theta in the interval

If veca and vecb are unit vectors inclined at an angle theta , then the value of |veca-vecb| is

Let veca and vecb are unit vectors inclined at an angle alpha to each other , if |veca+vecb| lt 1 then

If veca and vecb are unit vectors making an angle alpha with each other, such that alpha in (0, pi) and |veca+2vecb|lt 5 , then alpha lies in the interval

If veca and vecb are two vectors and angle between them is theta , then

If 6sin^(2)theta - sin theta = 1 and 0 le theta le pi , what is the value of sin theta ?

If |veca+ vecb| lt | veca- vecb| , then the angle between veca and vecb can lie in the interval

Two vectors vecA and vecB inclined at an angle theta have a resultant vecR which makes an angle alpha with vecA and angle beta with vecB . Let the magnitudes of the vectors vecA, vecB and vecR be represented by A, B and R respectively. Which of the following relations is not correct ?

vectors veca and vecb are inclined at an angle theta = 60^(@). " If " |veca|=1, |vecb| =2 , " then " [ (veca + 3vecb) xx ( 3 veca -vecb)] ^(2) is equal to

Let veca and vecb are two vectors inclined at an angle of 60^(@) , If |veca|=|vecb|=2 ,the the angle between veca and veca + vecb is