If vector `veca+vecb` bisects the angle between `veca and vecb`, then prove that `|veca|=|vecb|`.

If veca . vecb =ab then the angle between veca and vecb is

The vector veca+vecb bisects the angle between the vectors hata and hatb if (A) |veca|+|vecb|=0 (B) angle between veca and vecb is zero (C) |veca|=|vecb|=0 (D) none of these

If |vecA xx vecB| = vecA.vecB then the angle between vecA and vecB is :

For any two vectors veca and vecb prove that |veca.vecb|<=|veca||vecb|

If |veca - vecb|=|veca| =|vecb|=1 , then the angle between veca and vecb , is

If vecA*vecB=|vecAxxvecB| . Then angle between vecA and vecB is

If veca * vecb = |veca xx vecb| , then this angle between veca and vecb is,

If veca and vecb are unit vectors, then angle between veca and vecb for sqrt3 ​ veca − vec b to be unit vector is

The vector veca+vecb bisects the angle between the non-collinear vectors vecaandvecb , if……..

What is the angle between veca and the resultant of veca+vecb and veca-vecb ?