`veca.(vecbxxvecc)` is called the scalar triple product of `veca,vecb,vecc` and is denoted by `[veca vecb vecc]`. If `veca,vecb,vecc` are coplanar then `[veca+vecb vecb+vecc vecc+veca ]`= (A) 1 (B) -1 (C) 0 (D) none of these

veca.(vecbxxvecc) is called the scalar triple product of veca,vecb,vecc and is denoted by [veca vecb vecc]. If veca, vecb, vecc are cyclically permuted the vaslue of the scalar triple product remasin the same. In a scalar triple product, interchange of two vectors changes the sign of scalar triple product but not the magnitude. in scalar triple product the the position of the dot and cross can be interchanged privided the cyclic order of vectors is preserved. Also the scaslar triple product is ZERO if any two vectors are equal or parallel. (A) [vecb-vecc vecc-veca veca-vecb] (B) [veca vecb vecc] (C) 0 (D) none of these

If veca,vecb,vecc are non coplanar vectors then ([veca+2vecb vecb+2cvecc vecc+2veca])/([veca vecb vecc])= (A) 3 (B) 9 (C) 8 (D) 6

If veca + 2 vecb + 3 vecc = vec0 " then " veca xx vecb + vecb xx vecc + vecc xx veca=

If veca, vecb, vecc are vectors such that veca.vecb=0 and veca + vecb = vecc then:

If |veca|=1,|vecb|=2,|vecc|=3and veca+vecb+vecc=0 the show that veca.vecb+vecb.vecc+vecc.veca=- 7

If veca , vecb , vecc are unit vectors such that veca+ vecb+ vecc= vec0 find the value of (veca* vecb+ vecb* vecc+ vecc*veca) .

if veca + vecb + vecc=0 , then show that veca xx vecb = vecb xx vecc = vecc xx veca .

Let veca,vecb and vecc be three vectors. Then scalar triple product [veca vecb vecc] is equal to

If veca, vecb, vecc are any three non coplanar vectors, then (veca+vecb+vecc).(vecb+vecc)xx(vecc+veca)

The scalar triple product [(veca+vecb-vecc,vecb+vecc-veca,vecc+veca-vecb)] is equal to