Let A,B,C be vertices of a triangle ABC in which B is taken as origin of reference and position vectors of A and C are `veca and vecc` respectively. A line AR parallel to BC is drawn from A PR (P is the mid point of AB) meets AC and Q and area of triangle ACR is 2 times area of triangle ABC: (( PQ)/(QR)).((AQ)/(QC))` is equal to (B) ``1/10` (C) `2/5` (D) `3/5`