Find the reflection of the point `(alpha, beta, gamma)` in the XY-plane, YZ-plane.

The reflection of the point P (alpha, beta, gamma) in the xy-plane is

Find the the image of the point (alpha, beta, gamma) with respect to the plane 2x+y+z=6 .

The equations of the line through the point (alpha, beta, gamma) and equally inclined to the axes are (A) x-alpha=y-beta=z-gamma (B) (x-1)/alpha=(y-1)/beta=(z-1)/gamma (C) x/alpha=y/beta=z/gamma (D) none of these

Let alpha,beta, gamma be three real numbers satisfying [(alpha,beta,gamma)][(2,-1,1),(-1,-1,-2),(-1,2,1)]=[(0,0,0)] . If the point A(alpha, beta, gamma) lies on the plane 2x+y+3z=2 , then 3alpha+3beta-6gamma is equal to

Find the image of the point (4, 5, 7) in XY-plane.

Find the distance of the point (2, 3, 5) from the xy-plane.

Find the image of the point (-4, 0, -1) in YZ-plane.

Find the image of the point in the specified plane: (-3,4,7) in YZ-plane.

A variable plane passes through a fixed point (alpha,beta,gamma) and meets the axes at A ,B ,a n dCdot show that the locus of the point of intersection of the planes through A ,Ba n dC parallel to the coordinate planes is alphax^(-1)+betay^(-1)+gammaz^(-1)=1.

Let x-ysin alpha-zsin beta=0 , xsin alpha+zsin gamma-y=0 and xsin beta+ysin gamma-z=0 be the equations of the planes such that alpha+beta+gamma=pi//2 (where alpha,beta and gamma!=0)dot Then show that there is a common line of intersection of the three given planes.