Find the coordinates of the centroid of the triangle whose vertices are `(x_1,y_1,z_1)`, `(x_2,y_2,z_2)`and `(x_3,y_3,z_3)`.

Show that the coordinates off the centroid of the triangle with vertices A(x_1, y_1, z_1),\ B(x_2, y_2, z_2)a n d\ (x_3, y_3, z_3) are ((x_1+x_2+x_3)/3,(y_1+y_2+y_3)/3,(z_1+z_2+z_3)/3)

Show that the centroid of the triangle with vertices A(x_1,\ y_1,\ z_1) , B(x_2,\ y_2,\ z_2) and A(x_3,\ y_3,\ z_3) has the coordinates (("x"_1+"x"_2+"x"_2)/3,("y"_1+"y"_2+"y"_2,)/3("z"_1+"z"_2+"z"_2)/3)

STATEMENT-1 : The centroid of a tetrahedron with vertices (0, 0,0), (4, 0, 0), (0, -8, 0), (0, 0, 12)is (1, -2, 3). and STATEMENT-2 : The centroid of a triangle with vertices (x_(1), y_(1), z_(1)), (x_(2), y_(2), z_(2)) and (x_(3), y_(3), z_(3)) is ((x_(1)+x_(2)+x_(3))/3, (y_(1)+y_(2)+y_(3))/3, (z_(1)+z_(2)+z_(3))/3)

Find the perimeter of a triangle whose sides are 2y+3z, z-y, 4y-2z .

Show that the area of the triangle having vertices (0,0,0),(x_1,y_1,z_1),(x_2,y_2,z_2) is 1/2 sqrt((y_1z_2-y_2z_1)^2+(z_2x_1-x_2z_1)^2+(x_1y_2-x_2y_1)^2) .

A tetrahedron is a three dimensional figure bounded by four non coplanar triangular plane.So a tetrahedron has four no coplnar points as its vertices. Suppose a tetrahedron has points A,B,C,D as its vertices which have coordinates (x_1,y_1,z_1)(x_2,y_2,z_2),(x_3,y_3,z_3) and (x_4,y_4,z_4) respectively in a rectangular three dimensional space. Then the coordinates of its centroid are ((x_1+x_2+x_3+x_3+x_4)/4, (y_1+y_2+y_3+y_3+y_4)/4, (z_1+z_2+z_3+z_3+z_4)/4) . the circumcentre of the tetrahedron is the center of a sphere passing through its vertices. So, this is a point equidistant from each of the vertices of the tetrahedron. Let a tetrahedron have three of its vertices represented by the points (0,0,0) ,(6,-5,-1) and (-4,1,3) and its centroid lies at the point (1,2,5). The coordinate of the fourth vertex of the tetrahedron is

A plane meets the coordinate axes at P, Q and R such that the centroid of the triangle is (3,3,3). The equation of he plane is (A) x+y+z=9 (B) x+y+z=1 (C) x+y+z=3 (D) 3x+3y+3z=1

A tetrahedron is three dimensional figure bounded by four non coplanar triangular plane. So a tetrahedron has points A,B,C,D as its vertices, which have coordinates (x_(1),y_(1),z_(1)) (x_(2), y_(2), z_(2)) , (x _(3), y_(3) , z_(3)) and (x _(4), y _(4), z _(4)) respectively in a rectangular three –dimensional space. Then the coordinates of its centroid are ((x_(1)+ x_(2) + x _(3) + x_(4))/(4) , (y _(1) + y _(2) + y_(3) + y _(4))/(4), (z_(1) + z_(2) + z_(3)+ z_(4))/(4)). The circumcentre of the tetrahedron is the centre of a sphere passing through its vertices. So, the circumcentre is a point equidistant from each of the vertices of tetrahedron. Let tetrahedron has three of its vertices represented by the points (0,0,0) ,(6,-5,-1) and (-4,1,3) and its centroid lies at the point (1,-2,5). Now answer the following questions The distance between the planes x + 2y- 3z -4 =0 and 2x + 4y - 6z=1 along the line x/1= (y)/(-3) = z/2 is :

Let x_1y_1z_1,x_2y_2z_2 and x_3y_3z_3 be three 3-digit even numbers and Delta=|{:(x_1,y_1,z_1),(x_2,y_2,z_2),(x_3,y_3,z_3):}| . then Delta is

If a x_1^2+b y_1^2+c z_1^2=a x_2 ^2+b y_2 ^2+c z_2 ^2=a x_3 ^2+b y_3 ^2+c z_3 ^2=d ,a x_2 x_3+b y_2y_3+c z_2z_3=a x_3x_1+b y_3y_1+c z_3z_1=a x_1x_2+b y_1y_2+c z_1z_2=f, then prove that |(x_1, y_1, z_1), (x_2, y_2, z_2), (x_3,y_3,z_3)|=(d-f){((d+2f))/(a b c)}^(1//2)