Find the intercepts made on the coordinate axes by the plane `2x+y-2z=3` and find also the direction cosines of the normal to the plane.

Reduce the equation of the plane x-2y-2z=12 to normal form and hence find the length of the perpendicular for the origin to the plane. Also, find the direction cosines of the normal to the plane.

Reduce the equation 2x-3y-6z=14 to the normal form and hence fine the length of perpendicular from the origin to the plane. Also, find the direction cosines of the normal to the plane.

The direction cosines of the normal to the plane x + 2y - 3z + 4 = 0 are

Find the direction cosines of x, y and z-axis.

Find the direction cosines of x, y and z-axis.

The projection of a vector on the coordinate axes are 6,-3,2. Find its length and direction cosines,

The projection of a vector on the coordinate axes are (6,-3,2) Find its length and direction cosines.

Find the intercepts cut off by the plane 2x + y- z = 5 .

The intercepts of the plane 5x-3y+6z-60=0 on the coordinate axes are

Find the sum of the intercepts made by the plane 2x+3y-4z=12 on the coordinate axes is