Find a unit normal vector to the plane `x+2y+3z-6=0.`

Find a normal vector to the plane x+2y+3z-6=0

Find a normal vector to the plane 2x-y+2z=5. Also, find a unit vector normal to the plane.

The unit vector normal to the plane x + 2y +3z-6 =0 is (1)/(sqrt(14)) hati + (2)/(sqrt(14))hatj + (3)/(sqrt(14))hatk.

Show that the normal vector to the plane 2x+2y+2z=3 is equally inclined with the coordinate axes.

Find the normal form of the plane x+2y-2z+6=0 . Also find the length of perpendicular from origin to this plane and the d.c.'s of the normal.

Find the angles at which the normal vector to the plane 4x+8y+z=5 is inclined to the coordinate axes.

Find a vector of magnitude 26 units normal to the plane 12 x-3y+4z=1.

The direction cosines of the normal to the plane x + 2y - 3z + 4 = 0 are

Find equation of angle bisector of plane x+2y+3z-z=0 and 2x-3y+z+4=0 .

Find the normal form of the plane 2x+3y-z = 5 . Also find the length of perpendicular from origin and d.c's of the normal to the plane.