Find the points of intersection of the line `(x-2)/(-3)=(y-1)/2=(z-3)/2` and the plane `2x+y-z=3`.

Column I, Column II Image of the point (3,5,7) in the plane 2x+y+z=-18 is, p. (-1,1,-1) The point of intersection of the line (x-2)/(-3)=(y-1)/(-2)=(z-3)/2 and the plane 2x+y-z=3 is, q. (-21 ,-7,-5) The foot of the perpendicular from the point (1,1,2) to the plane 2x-2y+4z+5=0 is, r. (5/2,2/3,8/3) The intersection point of the lines (x-1)/2=(y-2)/3=(z-3)/4a n d(x-4)/5=(y-1)/2=z is, s. (-1/(12),(25)/(12),(-2)/(12))

find that the distance of the point of intersection of the line (x-2)/3=(y+1)/4=(z-2)/12 and the plane (x-y+z=5) from the point (-1,-5,-10) is

The disatance of the point (1, 0, 2) from the point of intersection of the line (x-2)/(3)=(y+1)/(4)=(z-2)/(12) and the plane x-y+z=16 , is

On which of the following lines lies the point of intersection of the line, (x-4)/(2)=(y-5)/(2)=(z-3)/(1) and the plane, x+y+z=2 ?

Find the distance of the point (-1,-5,-10) from the point of intersection of the line (x-2)/3=(y+1)/4=(z-2)/(12) and plane x-y+z=5.

Find the distance of the point (-1,-5,-10) from the point of intersection of the line (x-2)/3=(y+1)/4=(z-2)/(12) and plane x-y+z=5.

Find the equation of the line passing through the point "P"(4,6,2) and the point of intersection of the line ("x"-1)/3="y"/2=("z"+1)/7 and the plane "x"+"y"-"z"=8.

Which of the following line is passing through point of intersection of line (x-4)/(2)=(y-3)/(2)=(z-5)/(1) and the plane x+y+z=2 (a) (x)/(2)=(y+1)/(3)=(z-3)/(4) (b) (x-2)/(3)=(y-1)/(3)=(z-3)/(2) (c) (x)/(2)=(y+1)/(3)=(z-2)/(4) (d) (x-2)/(2)=(y+1)/(3)=(z+3)/(4)

Find the distance between the point (-1, -5, -10) and the point of intersection of line (x-2)/(3) = (y+1)/(4) = (z-2)/(12) and plane x-y + z =5

Find the equations of the projection of the line (x+1)/- 2=(y-1)/3=(z+2)/4 on the plane 2x+y+4z=1