Determine the direction cosines of the normal to the plane and its distance from the origin: `2x-3y+4z-6=0`

In each of the following cases,determine the direction cosines of the normal to the plane ned its distance from the origin: 5y+8=0

In each of the following cases, determine the direction cosines of the normal to the plane and the distance from the origin.(a) z = 2 (b) x + y + z = 1 (c) 2x + 3y z = 5 (d) 5y + 8 = 0

The direction cosines of the normal to the plane x + 2y - 3z + 4 = 0 are

Find the coordinates of the foot of the perpendicular drawn from the origin to the plane 2x-3y+4z-6=0.

An equation of a plane parallel to the plane x-2y+2z-5=0 and at a unit distance from the origin is

Find the coordinates of the foot of the perpendicular drawn from the origin to the plane 2x - 3y + 4z - 6 = 0 .

The direction cosines of the line 6x-2=3y+1=2z-2 are

The direction cosines of the line 6x-2=3y+1=2z-2 are

What are the direction cosines of the normal to the plane 4x+12y+3z=65? Also find the lenth of perpendicular from the origin to the plane.

In the following cases, find the coordinates of the foot of the perpendicular drawn from the origin.(a) 2x + 3y + 4z - 12 = 0 (b) 3y + 4z - 6 = 0 (c) x + y + z = 1 (d) 5y + 8 = 0