The equation of the plane through the origin and parallel to the plane `3x-4y+5z-6=0` is
(A) `3x-4y-5z-6=0`
(B) `3x-4y+5z+6=0`
(C) `3x-4y+5z - 6=0`
(D) `3x+4y-5z+6=0`

Equation of the passing through the origin and perpendicular to the planes x+2y+z=1 , 3x-4y+z=5 is

The equation of the plane through the point (1,2,-3) which is parallel to the plane 3x-5y+2z=11 is given by (A) 3x-5y+2z-13=0 (B) 5x-3y+2z+13=0 (C) 3x-2y+5z+13=0 (D) 3x-5y+2z+13=0

The equationof the plane passing through the origin and containing the line (x-1)/5=(y-2)/4=(z-3)/5 is (A) x+5y-3z=0 (B) x-5y+3z=0 (C) x-5y-3z=0 (D) 3x-10y+5z=0

The equation of the line passing through (1, 2, 3) and parallel to the planes x-y + 2z = 5 and 3x + y + z = 6 is.

The equation of the plane containing the line 2x-5y+z=3, x+y+4z=5 and parallel to the plane x+3y+6z=1 , is

Assertion: The equation of the plane thorugh the orign and parallel to the plane 3x-4y+5z-6=0 is 3x-4y=5z=0 Reason: The normals of two parallel planes are always parallel. (A) Both A and R are true and R is the correct explanation of A (B) Both A and R are true R is not the correct explanation of A (C) A is true but R is false. (D) A is false but R is true.

Find the equation of the plane passing through the point (-1,-1,2)a n d perpendicular to the planes 3x+2y-3z=1 a n d5x-4y+z=5.

Find the equation of a plane passes through the point (0 ,0,0) and perpendicular to each to the planes x+2y-z=1 and 3x-4y+z=5 .

The equation of the plane passing through the intersection of the planes x+2y+3z+4=0a dn 4x+3y+2z+1=0 and the origin ils (A) 3x+2y+z+1=0 (B) 3x+2y+z=0 (C) 2x+3y+z=0 (D) x+y+z=0

The equation of the plane thorugh the point (-1,2,0) and parallel to the lines x/3=(y+1)/0=(z-2)/(-1) and (x-1)/1=(2y+1)/2=(z+1)/(-1) is (A) 2x+3y+6z-4=0 (B) x-2y+3z+5=0 (C) x+y-3z+1=0 (D) x+y+3z-1=0