The points `(3,-2,-1),(-1,1,2),(2,3,-4) and (4,5,lamda)` are coplanar when `lamda= (A) 0 (B) `(-146)/17` (C) 1 (D) `(-17)/9`

The points A-=(3,10),B-=(12,-5)and C-=(lamda,10) are collinear then lamda= (A) 3 (B) 4 (C) 5 (D) none of these

Prove that the points A(9,-1,4),B(-1,-3,2) and C(4,-2,3) are collinear.

Plot the points A(4,1),B(-3,2),C(2,-3),D(-4,1),E(-4,-4) .

If |(a,a^2,1+a^3),(b,b^2,1+b^3),(c,c^2,1+c^3)|=0 and vectors (1,a,a^2),(1,b,b^2) and (1,c,c^2) are non coplanar then the product abc equals (A) 2 (B) -1 (C) 1 (D) 0

If the four points with position vectors -2hati+hatj+hatk, hati+hatj+hatk, hatj-hatk and lamda hatj+hatk are coplanar then lamda= (A) 1 (B) 2/3 (C) -1 (D) 0

If the vectors veca=2hati-hatj+hatk, vecb=hati+2hatj-hat(3k) and vecc= 3hati+lamda hatj+5hatk are coplanar the value of lamda is (A) -1 (B) 3 (C) -4 (D) -1/4

The points A(1,1,0),B(0,1,1),C(1,0,1) and D(2/3,2/3,2/3) are (A) coplanar (B) non coplanar (C) vertices of a parallelogram (D) none of these

If the straight lines (x+1)/2=(-y+1)/3=(z+1)/(-2)and (x-3)/1=(y-lamda)/2=z/3 intersect then the value of lamda is (A) -5/8 (B) -17/8 (C) -13/8 (D) -15/8

The points A(1,1,0),B(0,1,1),C(1,0,1) and D(2/3, 2/3, 2/3) are (A) coplanar (B) non coplanar (C) vertices of a paralleloram (D) none of these

If the straighat lines x=1+s,y=-3-lamdas,z=1+lamdas and x=t/2,y=1+t,z=2-t with parameters s and t respectively, are coplanar, then lamda equals (A) -1/2 (B) -1 (C) -2 (D) 0