The distance of the point `(2,1,-1)` from the plane `x-2y + 4z =9` is

Find the distance of the point (2, 3, 4) from the plane 3x + 2y + 2z + 5= 0 measured parallel to the line (x+3)/3=(y-2)/6=z/2 .

Find the distance of the point (2, 3, -5) from the plane x+2y-2z-9=0.

Find the distance of the point (1,0,-3) from the plane x-y-z=9 measured parallel to the line (x-2)/2=(y+2)/2=(z-6)/(-6)dot

Find the distance of the point (0.-3. -2) from the plane x + 2y - z = 1 measured parallel to (x+1)/2 = (y+1)/2 = z/3

A plane P = 0 passing through the point (1, 1, 1) is perpendicular to the planes 2x-y+2z=5 and 3x+6y-2z=7 . If the distance of the point (1, 2, 3) from the plane P = 0 is k units, then the value of 34k^(2) is equal to

The distance of the point (1, 2, 3) from the plane x+y-z=5 measured along the straight line x=y=z is

Find the perpendicular distance from the point P(2, 3, -4) to the plane x+ 2y + 3z = 13.

Find the coordinates of the foot of the perpendicular and the perpendicular distance of the point P(3,2,1) from the plane 2x-y+z+1=0. Find also, the image of the point in the plane.

Find the distance of the point (1,2,0) from the plane 4x+3y+12z+16=0

Find the distance of the point (1,0,-3) from plane x-y-z=9 measured parallel to the line (x-2)/2=(y+2)/2=(z-6)/(-6)