If the line `(x-4)/(1)=(y-2)/(1)=(z-k)/(2)` lies exactly on the plane `2x-4y+z=7`, the value of k is

If the line (x-4)/(1)=(y-2)/(1)=(z-m)/(2) lies in the plane 2x+ly+z=7 , then the value of m+2l is equal to

If the line (x-4)/(1)=(y-2)/(1)=(z-q)/(p) lies completely in the plane 2x-4y+z=7 , then the ordered pair (p, q) is

If the line, (x-3)/(1) =(y+2)/(-1) = (z+ lamda)/(-2) lies in the plane, 2x -4y + 3z =2, then the shortest distance between this line and the line, (x-1)/(12) = y/9 =z/4 is :

If the line (x-1)/(1)=(y-k)/(-2)=(z-3)/(lambda) lies in the plane 3x+4y-2z=6 , then 5|k|+3|lambda| is equal to

If the line (x-1)/(5)=(y-3)/(2)=(z-3)/(2) intersects the curve x^(2)-y^(2)=k^(2), z=0 , then the value of 2k can be equal to

The value of k such that (x-4)/1=(y-2)/1=(z-k)/2 lies in the plane 2x-4y+z=7 is a. 7 b. -7 c. no real value d. 4

If the lines (x-1)/2=(y+1)/3=(z-1)/4 and (x-3)/1=(y-k)/2=z/1 intersect, then find the value of k .

If the lines (x-1)/2=(y+1)/3=(z-1)/4a n d(x-3)/1=(y-k)/2=z/1 intersect, then find the value of kdot

if an angle between the line,and the plane, (x-1)/2=(y-2)/1=(z-3)/-2 and the plane x-2y-kz= 3 is cos^-1 (2sqrt2)/3 then a value of k is:

Find the angle between the line (x-1)/1=(y-2)/(-1)=(z+1)/1 and the plane 2x+y-z=4.