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Consider the L1:(x+1)/3=(y+2)/1=(z+1)/2 ...

Consider the `L_1:(x+1)/3=(y+2)/1=(z+1)/2 and L_2:(x-2)/1=(y+2)/2=(z-3)/3` The shortest distance betwen `L_1 and L_2` is
(A) 0 (B) `17/sqrt(3)` (C) `41/(5(3)` (D) `17/sqrt(75)`

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