Find the angle between planes `vecr.(veci+vecj)=1 and vecr.(veci+veck)=3`.

Find the cosine of the angle between the planes vecr.(2veci-3vecj-6veck)=7 and vecr.(6veci+2vecj-9veck)=5

Find the angle between the planes vecr.(hati+hatj-2hatk)=3 and vecr.(2hati-2hatj+hatk)=2 2

The angle between the planes vecr. (2 hati - 3 hatj + hatk) =1 and vecr. (hati - hatj) =4 is

The angle between the planes vecr.(2hati-hatj+hatk)=6 and vecr.(hati+hatj+2hatk)=5 is

If a vector vecr of magnitude 3sqrt6 is directed along the bisector of the angle between the vectors veca =7veci-4vecj -4veck and vecb = -2veci- vecj+ 2veck , then vecr is equal to

Find the angle between the planes 2x+y-2x+3=0 and vecr*(6hati+3hatj+2hatk)=5 .

The equation of the plane which contains the origin and the line of intersectio of the plane vecr.veca=d_(1) and vecr.vecb=d_(2) is

Find the angle between the folowing planes :- (i) vecr.(2hati-3hatj+4hatk) = 5 and vecr.(-hati+hatj) = 1 (ii) vecr.(2hati+3hatj-6hatk) = 1 and vecr.(hati-2hatj+2hatk) + 3 = 0 (iii) x+y-2z=3 and 2x-2y+z+1 = 0

Find the value of (veci-2j+veck)xx[(2veci+vecj+veck)xx(veci+2vecj-veck)]

Position vectors of two points A and C re 9veci-vecj+7veci-2vecj+7veck respectively THE point intersection of vectors vec(AB)=4veci-vecj+3veck and vec(CD)=2veci-vecj+2veck is P. If vector vec(PQ) is perpendicular to vec(AB) and vec(CD) and PQ=15 units find the position vector of Q.