The equation of the line through `(1,1,1)` and perpendicular to the plane ` 2x+3y-z=5` is
(A) `(x-1)/2=(y-1)/3=z-1`
(B) `(x-1)/2=(y-1)/3=(z-1)/(-1)`
(C) `(x-1)/2=(y-1)/3=(z-1)/(5)`
(D) `(x-1)/2=(y-1)/(-3)=z-1`

Equations of the line passing through (1,1,1) and perpendicular to the plane 2x+3y+z+5=0 are

The equation of the plane passing through the point (1,1,1) and perpendicular to the planes 2x+y-2z=5 and 3x-6y-2z=7

The equation of the plane passing through the point (1,1,1) and perpendicular to the planes 2x+y-2z=5 and 3x-6y-2z=7 is

Equation of theine passing through hati+hatj-3hatk and perpendiculr to the plane 2x-4y+3z+5=0 is (A) (x-1)/2=(1-y)/(-4)=(z-3)/3 (B) (x-1)/2=(1-y)/4=(z+3)/3 (C) (x-2)/1=(y+4)/1)=(z-3)/3 (D) (x-1)/(-2)=(1-y)/(-4)=(z-3)/3

Find the equation of the line passing through the point (2, 1, 3) and perpendicular to the lines (x-1)/1=(y-2)/2=(z-3)/3andx/(-3)=y/2=z/5

Find the equation of the plane through the point (-1,-1, 2) and perpendicular to the planes 3x + 2y - 3z = 1 and 5x - 4y + z = 5.

The line perpendicular to the plane 2x-y+5z=4 passing through the point (-1,0,1) is (A) (x+1)/2=-y=(z-1)/(-5) (B) (x+1)/(-2)=y=(z-1)/-5 (C) (x+1)/2=-y=(z-1)/5 (D) (x+1)/2=y=(z-1)/-5

Find the equation of a line passing through the point (-1,3,-2) and perpendicular to the lines: (x+2)/(-3)=(y-1)/(2)=(z+1)/5andx/1=y/2=z/3

The equation of the line passing through (-4, 3, 1), parallel to the plane x +2y-z-5=0 and intersecting the line (x+1)/-3=(y-3)/2=(z-2)/-1 A. (x+4)/1=(y-3)/1=(z-1)/3 B. (x+4)/3=(y-3)/(-1)=(z-1)/1 C. (x-4)/2=(y+3)/1=(z+1)/4 D. (x+4)/(-1)=(y-3)/1=(z-1)/1

Find the equation of the plane passing through the point (-1,-1,2)a n d perpendicular to the planes 3x+2y-3z=1 a n d5x-4y+z=5.