Home
Class 12
MATHS
The line perpendicular to the plane 2x-y...

The line perpendicular to the plane `2x-y+5z=4` passing through the point (-1,0,1) is
(A) `(x+1)/2=-y=(z-1)/(-5)`
(B) `(x+1)/(-2)=y=(z-1)/-5`
(C) `(x+1)/2=-y=(z-1)/5`
(D) `(x+1)/2=y=(z-1)/-5`

Promotional Banner

Similar Questions

Explore conceptually related problems

The equation of the line through (1,1,1) and perpendicular to the plane 2x+3y-z=5 is (A) (x-1)/2=(y-1)/3=z-1 (B) (x-1)/2=(y-1)/3=(z-1)/(-1) (C) (x-1)/2=(y-1)/3=(z-1)/(5) (D) (x-1)/2=(y-1)/(-3)=z-1

The equation to the striaghat line passing through the points (4,-5,-2) and (-1,5,3) is (A) (x-4)/1=(y+5)/(-2)=(z+2)/(-1) (B) (x+1)/1=(y-5)/2=(z-3)/(-1) (C) x/(-1)=y/5=z/3 (D) x/4=y/(-5)=z/(-2)

Equation of theine passing through hati+hatj-3hatk and perpendiculr to the plane 2x-4y+3z+5=0 is (A) (x-1)/2=(1-y)/(-4)=(z-3)/3 (B) (x-1)/2=(1-y)/4=(z+3)/3 (C) (x-2)/1=(y+4)/1)=(z-3)/3 (D) (x-1)/(-2)=(1-y)/(-4)=(z-3)/3

The line through of the plane passing through the lines (x-4)/(1)=(y-3)/(1)=(z-2)/(2) and (x-3)/(1)=(y-2)/(-4)=(z)/(5) is

Equation of a line in the plane pi =2x-y+z-4=0 which is perpendicular to the line l whose equation is (x-2)/1=(y-2)/(-1)=(z-3)/(-2) and which passes through the point of intersection of l and pi is (A) (x-2)/1=(y-1)/5=(z-1)/(-1) (B) (x-1)/3=(y-3)/5=(z-5)/(-1) (C) (x+2)/2=(y+1)/(-1)=(z+1)/1 (D) (x-2)/2=(y-1)/(-1)=(z-1)/1

The equation of the plane containing the line 2x+z-4=0 nd 2y+z=0 and passing through the point (2,1,-1) is (A) x+y-z=4 (B) x-y-z=2 (C) x+y+z+2=0 (D) x+y+z=2

A plane which passes through the point (3,2,0) nd the line (x-4)/1=(y-7)/5=(z-4)/4 is (A) x-y+z=1 (B) x+y+z=5 (C) x+2y-z=1 (D) 2x-y+z=5

The image of the line (x-1)/3=(y-3)/1=(z-4)/(-5) in the plane 2x-y+z+3=0 is the line (1) (x+3)/3=(y-5)/1=(z-2)/(-5) (2) (x+3)/(-3)=(y-5)/(-1)=(z+2)/5 (3) (x-3)/3=(y+5)/1=(z-2)/(-5) (3) (x-3)/(-3)=(y+5)/(-1)=(z-2)/5

Determine the equation of the line passing through the point (-1,3,-2) and perpendicualr to the lines: x/1 = y/2 = z/3 and (x +2)/(-2) = (y-1)/(2) = (z+1)/(5)

Find the equation of the line passing through the point (2, 1, 3) and perpendicular to the lines (x-1)/1=(y-2)/2=(z-3)/3andx/(-3)=y/2=z/5