Foot of the perpendicular form (-2,1,4) to a plane `pi` is (3,1,2). Then the equation of theplane `pi` is (A) `4x-2y=11` (B) `5x-2y=10` (C) `5x-2z=11` (D) `5x+2z=11`

A plane through the line (x-1)/1=(y+1)/(-2)=z/1 has the equation (A) x+y+z=0 (B) 3x+2y-z=1 (C) 4x+y-2z=3 (D) 3x+2y+z=0

Column I, Column II Image of the point (3,5,7) in the plane 2x+y+z=-18 is, p. (-1,1,-1) The point of intersection of the line (x-2)/(-3)=(y-1)/(-2)=(z-3)/2 and the plane 2x+y-z=3 is, q. (-21 ,-7,-5) The foot of the perpendicular from the point (1,1,2) to the plane 2x-2y+4z+5=0 is, r. (5/2,2/3,8/3) The intersection point of the lines (x-1)/2=(y-2)/3=(z-3)/4a n d(x-4)/5=(y-1)/2=z is, s. (-1/(12),(25)/(12),(-2)/(12))

The equation of the plane through the point (1,2,-3) which is parallel to the plane 3x-5y+2z=11 is given by (A) 3x-5y+2z-13=0 (B) 5x-3y+2z+13=0 (C) 3x-2y+5z+13=0 (D) 3x-5y+2z+13=0

Find the length and the foot of perpendicular from the point (1,3//2,2) to the plane 2x-2y+4z+5=0.

Find the length and the foot of perpendicular from the point (1,3//2,2) to the plane 2x-2y+4z+5=0.

Find the length and the foot of perpendicular from the point (1,3//2,2) to the plane 2x-2y+4z+5=0.

A plane which passes through the point (3,2,0) nd the line (x-4)/1=(y-7)/5=(z-4)/4 is (A) x-y+z=1 (B) x+y+z=5 (C) x+2y-z=1 (D) 2x-y+z=5

The line perpendicular to the plane 2x-y+5z=4 passing through the point (-1,0,1) is (A) (x+1)/2=-y=(z-1)/(-5) (B) (x+1)/(-2)=y=(z-1)/-5 (C) (x+1)/2=-y=(z-1)/5 (D) (x+1)/2=y=(z-1)/-5

Find the length and the foot of the perpendicular drawn from the point (2, -1,5) to the line (x -11)/10=(y + 2)/-4=(z+ 8)/-11

Find the equation of the plane passing through the point (-1,-1,2)a n d perpendicular to the planes 3x+2y-3z=1 a n d5x-4y+z=5.