Equation of theine passing through `hati+hatj-3hatk` and perpendiculr to the plane 2x-4y+3z+5=0 is (A) `(x-1)/2=(1-y)/(-4)=(z-3)/3` (B) `(x-1)/2=(1-y)/4=(z+3)/3` (C) `(x-2)/1=(y+4)/1)=(z-3)/3` (D) `(x-1)/(-2)=(1-y)/(-4)=(z-3)/3`

Equation of the passing through the origin and perpendicular to the planes x+2y+z=1 , 3x-4y+z=5 is

The equation of the line through (1,1,1) and perpendicular to the plane 2x+3y-z=5 is (A) (x-1)/2=(y-1)/3=z-1 (B) (x-1)/2=(y-1)/3=(z-1)/(-1) (C) (x-1)/2=(y-1)/3=(z-1)/(5) (D) (x-1)/2=(y-1)/(-3)=z-1

The line (x-2)/1=(y+4)/(2)=(z-3)/3 and x/2=(y-1)/(4)=(z+3)/(6) are

Equation of the plane passing through the point (1,1,1) and perpendicular to each of the planes x+2y+3z=7 and 2x-3y+4z=0 l is

Find the equation of the plane passing through the point (-1,-1,2)a n d perpendicular to the planes 3x+2y-3z=1 a n d5x-4y+z=5.

The equation of the line passing through (-4, 3, 1), parallel to the plane x +2y-z-5=0 and intersecting the line (x+1)/-3=(y-3)/2=(z-2)/-1 A. (x+4)/1=(y-3)/1=(z-1)/3 B. (x+4)/3=(y-3)/(-1)=(z-1)/1 C. (x-4)/2=(y+3)/1=(z+1)/4 D. (x+4)/(-1)=(y-3)/1=(z-1)/1

The lines x/1=y/2=z/3 and (x-1)/(-2)=(y-2)/(-4)=(z-3)/(-6) are

Find the equation of the plane through the point (-1,-1, 2) and perpendicular to the planes 3x + 2y - 3z = 1 and 5x - 4y + z = 5.

Find the equation of the plane passing through the oint (-1,-1,2) and perpendicular to each of tehpalnes 2x+3y-3z=2 and 5x-4y+z=6 .

The equation of the line intersection of the planes 4x+4y-5z=12 and 8x+12y-13z=32 can be written as: (A) x/2=(y-1)/3=(z-2)/4 (B) x/2=y/3=(z-2)/4 (C) (x-1)/2=(y-2)/3=z/4 (D) (x-1)/2=(y-2)/(-3)=z/4