If C is the mid point of AB and P is any point outside AB then (A) `vec(PA)+vec(PB)+vec(PC)=0` (B) `vec(PA)+vec(PB)+2vec(PC)=vec0` (C) `vec(PA)+vec(PB)=vec(PC)` (D) `vec(PA)+vec(PB)=2vec(PC)`

If vec(A)+vec(B)+vec(C )=0 then vec(A)xx vec(B) is

In triangle ABC (Figure), which of the following is not true: (A) vec(AB)+ vec(BC)+ vec(CA)=vec0 (B) vec(AB)+ vec(BC)- vec(AC) =vec0 (C) vec(AB)+ vec(BC)- vec(CA)=vec0 (D) vec(AB)+ vec(CB)+ vec(CA)=vec0

Prove that vec(a). {(vec(b) + vec(c)) xx (vec(a) + 2vec(b) + 3vec(c))} = [vec(a) vec(b) vec(c)] .

If vec( A) + vec(B) =vec( C ) , and | vec(A)| =2 | vec( B) | and vec( B). vec( C ) = 0 , then

If [ 2 vec (a) - 3 vec(b) vec( c ) vec(d)] =lambda [vec(a) vec(c ) vec(d) ] + mu [ vec(b) vec( c ) vec( d) ] , then 2 lambda + 3 mu=

If vec(a) , vec( b) and vec( c ) are unit vectors such that vec(a) + vec(b) + vec( c) = 0 , then the values of vec(a). vec(b)+ vec(b) . vec( c )+ vec( c) .vec(a) is

If vec(a)+vec(b)+vec(c )=0 " and" |vec(a)|=3,|vec(b)|=5, |vec(c )|=7 , then find the value of vec(a)*vec(b)+vec(b)*vec(c )+vec(c )*vec(a) .

If the position vector of these points are vec(a) -2vec(b)+3 vec(c ), 2 vec(a)+3vec(b)-4 vec( c) ,-7 vec(b) + 10 vec(c ) , then the three points are

Three vector vec(A) , vec(B) , vec(C ) satisfy the relation vec(A)*vec(B)=0 and vec(A).vec(C )=0 . The vector vec(A) is parallel to

Three vector vec(A) , vec(B) , vec(C ) satisfy the relation vec(A)*vec(B)=0 and vec(A).vec(C )=0 . The vector vec(A) is parallel to