If (a x b) x c = a x (b x c), where a, b and c are Any three vector such that `veca.vecb!=0, vecb.vecc!=0, then veca and vecc `are
(A) inclined at an angle `pi/6` between them
(B) perpendicular
(C) parallel
(D) inclined at an angle `pi/3` between them

If (vecaxxvecb)xxvecc=vecaxx(vecbxxvecc), Where veca, vecb and vecc and any three vectors such that veca.vecb=0,vecb.vecc=0, then veca and vecc are

If (vecaxxvecb)xxvecc=vecaxx(vecbxxvecc), where veca,vecb,vecc are any three vectors such that veca.vecb!=0,vecb.vecc!=0 , then veca and vecc are (A) inclined at an angle pi/3 to each other (B) inclined at an angle of pi/6 to each other (C) perpendicular (D) parallel

If veca, vecb, vecc are any three vectors such that (veca+vecb).vecc=(veca-vecb)vecc=0 then (vecaxxvecb)xxvecc is

Let vea, vecb and vecc be unit vectors such that veca.vecb=0 = veca.vecc . It the angle between vecb and vecc is pi/6 then find veca .

If veca, vecb, vecc are unit vectors such that veca. vecb =0 = veca.vecc and the angle between vecb and vecc is pi/3 , then find the value of |veca xx vecb -veca xx vecc|

Let vec a, vec b, vec c are three vectors such that veca .veca=vecb . vecb = vecc . vecc = 3 and |veca-vecb|^2+|vecb-vecc|^2+|vecc-veca|^2=27, then

If vec a , vec b , vec c are any three noncoplanar vector, then ( veca + vecb + vecc )[( veca + vecb )×( veca + vecc )] is :

Let veca, vecb, vecc be three unit vectors and veca.vecb=veca.vecc=0 . If the angle between vecb and vecc is pi/3 then find the value of |[veca vecb vecc]|

If veca and vecb are two vectors, such that veca.vecblt0 and |veca.vecb|=|vecaxxvecb| then the angle between the vectors veca and vecb is (a) pi (b) (7pi)/4 (c) pi/4 (d) (3pi)/4

Let vecA, vecB and vecC be unit vectors such that vecA.vecB = vecA.vecC=0 and the angle between vecB and vecC " be" pi//3 . Then vecA = +- 2(vecB xx vecC) .