The distance of the point `(1, 3, -7)` from the plane passing through the point `(1, -1, -1)` having normal perpendicular to both the lines `(x-1)/(1)=(y+2)/(-2)=(z-4)/(3) and (x-2)/(2)=(y+1)/(-1)=(z+7)/(-1)` is

Find the distance of the point (1,1,1) from the plane passing through the point (-1, -2, -1) and whose normal is perpendicular to both the lines. (x+1)/(3)=(y+2)/(1)= (z+1)/(2) and (x-2)/(1)= (y+2)/(2)= (z-3)/(3)

Read the following passage and answer the questions. Consider the lines L_(1) : (x+1)/(3)=(y+2)/(1)=(z+1)/(2) L_(2) : (x-2)/(1)=(y+2)/(2)=(z-3)/(3) Q. The distance of the point (1, 1, 1) from the plane passing through the point (-1, -2, -1) and whose normal is perpendicular to both the lines L_(1) and L_(2) , is

The distance of the point (1,-2,4) from the plane passing through the point (1,2,2) perpendicular to the planes x-y+2z=3 and 2x-2y+z+12=0 is

Find the equation of the lines passing through the point (2, 1, 3) and perpendicualr to the lines (x-1)/(1)=(y-2)/(2)=(z-3)/(3)andx/(-3)=y/(2)=z/(5) .

Find the equation of the line passing through the point (2, 1, 3) and perpendicular to the lines (x-1)/1=(y-2)/2=(z-3)/3andx/(-3)=y/2=z/5

Find the equation of a line passing through the point (-1,3,-2) and perpendicular to the lines: (x+2)/(-3)=(y-1)/(2)=(z+1)/5andx/1=y/2=z/3

The equation of the line passing though the point (1,1,-1) and perpendicular to the plane x -2y - 3z =7 is :

The equation of the plane passing through the point (1,1,1) and perpendicular to the planes 2x+y-2z=5 and 3x-6y-2z=7

The equation of the plane passing through the point (1,1,1) and perpendicular to the planes 2x+y-2z=5 and 3x-6y-2z=7 is

Find the equation of the plane passing through the points (-1,1,1) and (1,-1,1) and perpendicular to the plane x+2y+2z=5.