Given that `"log"_(10)2 = 0.30103, " log"_(10) 3 = 0.47712` (approximately), find the number of digits in `2^(8), 3^(12)`.

If log(2)=0.30103 find the number of digits in 2^(100)

If log_(10) 2 = 0.3010 and log_(10) 3 = 0.477 , then find the number of digits in the following numbers: (a) 3^(40)" "(b) 2^(22) xx 5^(25)" (c) 24^(24)

Find the value of log_(10)0.001

There are 3 number a, b and c such that log_(10) a = 5.71, log_(10) b = 6.23 and log_(10) c = 7.89 . Find the number of digits before dicimal in (ab^(2))/c .

If log10^(2) = .3010, log10^(3) = .4771 find log_(10)36

Find the number of digits in 4^(2013) , if log_(10) 2 = 0.3010.

If log 10^(2) = 0.3010 log 10^(3) = 0.4772 find log 10^(144)

Prove that 1/3<(log)_(10)3<1/2dot

If log_(2)(log_(2)(log_(2)x))=2 , then the number of digits in x, is (log_(10)2=0.3010)

Solve (x^(log_(10)3))^(2) - (3^(log_(10)x)) - 2 = 0 .