The perimeter of a triangle ABC is six times the arithmetic mean of the sines of its angles. If the side `a is 1` then find angle `Adot`

Explanation

Here,` a = 1`

It is given that,

`a+b+c = 6((sinA+sinB+sinC)/3)`

As `a = 2RsinA, b = 2RsinB and c = 2RsinC`

`=>2R(sinA+SinB+sinC) = 2(sinA+sinB+sinC)`

`=>R = 1`

Now, ` a = 2RsinA`

`1 = 2(1)sinA`

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