The number of values of `theta` in the interval `(-pi/2,pi/2)` satisfying the equation `(sqrt(3))^(sec^2theta)=tan^4theta+2tan^2theta` is

Find the values of theta in the interval (-pi/2,pi/2) satisfying the equation (1-tantheta)(1+tantheta)sec^2theta+2^tan^(2theta)=0

Solve sqrt(2) sec theta+tan theta=1 .

The number of values of theta in the interval [-pi/2,pi/2] and theta!=(npi)/5 is where n=0,+-1,+-2 and tantheta=cot(5theta) and sin(2theta)=cos(4theta) is

solve the equation tan^2 theta + cot ^2 theta =2 .

The value of theta lying between theta=0a n dtheta=pi/2 and satisfying the equation |1+sin^2thetacos^2theta4sin4thetasin^2theta1+cos^2theta4sin4thetasin^2thetacos^2theta1+4sin4theta|=0a r e (7pi)/(24) (b) (5pi)/(24) (c) (11pi)/(24) (d) pi/(24)

Solve 3(sec^(2) theta+tan^(2) theta)=5 .

Prove that tan^2 (theta)-sin^2 (theta)= tan^2 (theta) sin^2 (theta)

The general value of theta satisfying the equation tan^2theta+sec2theta=1 is_____

There exists a value of theta between 0 and 2pi that satisfies the equation sin^4theta-2sin^2theta-1=0