If `(secA+tanA)(secB+tanB)(secC+tanC)=``(secA-tanA)(secB-tanB)(secC-tanC),` prove that the value of each side is +-1.

Prove that (1)/(secA+tanA)=secA-tanA

Prove that (secA+tanA)/(sec^2 A- tan^2 A)=secA+tanA

Prove that secA(1-sinA)(secA+tanA)=1

Prove that : (tanA)/(secA-1)+(tanA)/(secA+1)=2cosecA

Prove that : (secA+tanA)(1-sinA)=cosA

prove that 1/(secA-tanA)-1/(cosA)=1/(cosA)-1/(secA+tanA)

Prove that sec A(1-sin A)(secA+tanA)=1 .

If tan^3A+tan^3B+tan^3C=3tanA* tanB*tanC , then prove that triangle ABC is an equilateral triangle.

If in a Delta ABC ,tanA+tanB+tanC=6, then cotA cotB cotC=

In triangle A B C ,tanA+tanB+tanC=6a n dtanAtanB=2, then the values of tanA ,tanB ,tanC are, respectively (a) 1,2,3 (b) 3,2//3,7//3 (c) 4,1//2 ,3//2 (d) none of these