`3(sintheta-costheta)^4+6(sintheta +costheta)^2+4(sin^6theta+cos^6theta)` is equal to 11 (b) 12 (c) 13 (d) 14

(costheta + isintheta)^4/(sintheta + icostheta)^5 is equal to.

(sintheta+sin2theta)/(1+costheta+cos2theta)

If sintheta +costheta =1 then sin^6 theta +cos^6 theta is:

If 5tantheta=4, then (5sintheta-3costheta)/(5sintheta+2costheta) is equal to 0 (b) 1 (c) 1/6 (d) 6

If x=(2sintheta)/(1+costheta+sintheta),t h e n(1-costheta+sintheta)/(1+sintheta) is equal to 1+x (b) 1-x (c) x (d) 1/x

If sintheta_1+sintheta_2+sintheta_3=3, then costheta_1+costheta_2+costheta_3 is equal to 3 (b) 2 (c) 1 (d) 0

If tantheta=(3)/(4)," find "(2sintheta+3costheta)/(3sintheta+2costheta) is:

If sintheta-costheta=1, then the value of sin^3theta-cos^3theta is __________

If sintheta=costheta then 2tan^(2)theta+sin^(2)theta-1=___ .