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If 5tantheta=4, then (5sintheta-3costhet...

If `5tantheta=4,` then `(5sintheta-3costheta)/(5sintheta+2costheta)` is equal to `0` (b) 1 (c) `1/6` (d) 6

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`5tantheta=4`
`tantheta=4/5`
`tantheta=sintheta/costheta`
`=(5sintheta-3costheta)/(5sintheta+2costheta)`
`=((5sintheta-3costheta)/costheta)/((5sintheta+2costheta)/costheta)`
`=(5tantheta-3)/(5tantheta+2)`
`=(5*4/5-3)/(5*4/5+2)`
`=(4-3)/(4+2)`
...
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