If `sintheta_1+sintheta_2+sintheta_3=3,` then `costheta_1+costheta_2+costheta_3` is equal to 3 (b) 2 (c) 1 (d) 0

costheta -sintheta -cottheta +1=0

If 5tantheta=4, then (5sintheta-3costheta)/(5sintheta+2costheta) is equal to 0 (b) 1 (c) 1/6 (d) 6

If sintheta +costheta =1 then sin^6 theta +cos^6 theta is:

If x=(2sintheta)/(1+costheta+sintheta),t h e n(1-costheta+sintheta)/(1+sintheta) is equal to 1+x (b) 1-x (c) x (d) 1/x

3(sintheta-costheta)^4+6(sintheta +costheta)^2+4(sin^6theta+cos^6theta) is equal to 11 (b) 12 (c) 13 (d) 14

If sintheta_1sintheta_2-costheta_1costheta_2+1=0, then the value of tan((theta_1)/2)cot((theta_2)/2) is equal to (a) -1 (b) 1 (c) 2 (d) -2

If 3sintheta+5costheta=5, then show that 5sintheta-3costheta=+-3.

(sintheta+sin2theta)/(1+costheta+cos2theta)

If sintheta=(5)/(13)" then "costheta=?