If `sinx+sin^2x=1` then the value of `tan^8x-tan^4x-2tan^2x+1` will be equal to 0 (b) 1 (c) 2 (d) 3

If secx+sec^2x=1 then the value of tan^8x-tan^4x-2tan^2x+1 will be equal to 0 (b) 1 (c) 2 (d) 3

If sin^(-1)((1)/(2))=tan^(-1)x, then find the value of x.

Solve (tan3x-tan2x)/(1+tan3xtan2x )=1

The value of (lim)_(xvecoo)(tan^(-1)x))) is equal to (a)-1 (b) pi/2 (c) -1/(sqrt(2)) (d) 1/(sqrt(2))

Let |[tan^(-1)x,tan^(-1)2x,tan^(-1)3x],[tan^(-1)3x,tan^(-1)x,tan^(-1)2x],[tan^(-1)2x,tan^(-1)3x,tan^(-1)x]| =0 , then the number of values of x satisfying the equation is (a) 1 (b) 2 (c) 3 (d) 4

The value of 2tan^(-1)(cos e ctan^(-1)x-tancot^(-1)x) is equal to (a) cot^(-1)x (b) cot^(-1)1/x (c) tan^(-1)x (d) none of these

("lim")_(xvec0)(x^4(cot^4x-cot^2x+1)/((tan^4x-tan^2x+1)i se q u a lto 1 (b) 0 (c) 2 (d) none of these

("lim")_(xvecoo)(sin^4x-sin^2x+1)/(cos^4x-cos^2x+1) is equal to (a) 0 (b) 1 (c) 1/3 (d) 1/2

The number of solutions of the equation cos6x+tan^2x+cos(6x)tan^2x=1 in the interval [0,2pi] is (a) 4 (b) 5 (c) 6 (d) 7

If x in (0, 1) , then find the value of tan^(-1) ((1 -x^(2))/(2x)) + cos^(-1) ((1 -x^(2))/(1 + x^(2)))