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In triangle A B C ,/A=60^0,/B=40^0,a n d...

In triangle `A B C ,/_A=60^0,/_B=40^0,a n d/_C=80^0dot` If `P` is the center of the circumcircle of triangle `A B C` with radius unity, then the radius of the circumcircle of triangle `B P C` is (a)1 (b) `sqrt(3)` (c) 2 (d) `sqrt(3)` `2`

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