A tower stands vertically on the ground. From a point which is 15 meter away from the foot of the tower, the angle of elevation of the top of the tower is `45^(@)`. What is the height of the tower?

Explanation

Let `h` is the height of the tower.

Then,

`AP = BP = CP = hcot theta`

Please refer to video to see the diagram.

Here, `P` is the circumcenter of `Delta APC`.

`:. AP = BP = CP = R = (abc)/(4Delta)`

`=>(abc)/(4Delta) = hcottheta`

`=>h = 1/cottheta(abc)/(4Delta)`

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