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Solve the equation 2sinx+cosy=2 for the ...

Solve the equation `2sinx+cosy=2` for the value of `xa n dydot`

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`2sinx+cosy = 2`
`=>cosy = 2(1-sinx)->(1)`
As `-1 le cosy le 1`
`:. -1 le 2(1-sinx) le 1`
`=> -1/2 le 1-sinx le 1/2`
`=> 1/2 le sinx le 3/2`
As maximum value of `sinx` can be `1`,
`:. 1/2 le sinx le 1`
...
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