If `sin^2(theta-alpha)c a salpha=cos^2(theta-alpha)sinalpha=msinalphacosalpha,` then prove that `|m|geq1/(sqrt(2))`

Explanation

`sin^2(theta-alpha)cosalpha=msinalphacosalpha`

`sin^2(theta-alpha)=msinalpha-(1)`

`cos^2(theta-alpha)sinalpha=msinalphacosalpha`

`cos^2(theta-alpha)=mcosalpha-(2)`

adding equation 1 and 2

`sin^2(theta-alpha)+cos^2(theta-alpha)=m(sinalpha+cosalpha)`

`1=m(sinalpha+cosalpha)`

`[sinalpha+cosalpha=1/m]1/sqrt2`

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