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If 2tan^(-1)x+sin^(-1)(2x)/(1+x^2) is in...

If `2tan^(-1)x+sin^(-1)(2x)/(1+x^2)` is independent of `x ,` then

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if|x|`<=`1 then `2tan^(-1)x=sin^(-1)((2x)/(1+x^2))`
If x>1 then `2tan^(-1)x=pi-sin^(-1)((2x)/(1+x^2))`
If x<-1, then `2tan^(-1)x=-pi-sin((2x)/(1+x^2))`
x>1 or x<-1
Option A and B are correct.
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