If `f(x)=(tan(pi/4+(log)_e x))^((log)_x e)` is to be made continuous at `x=1,` then what is the value of `f(1)?`

e ^(x log a)e^(x)

let f(x)=(lncosx)/{(1+x^2)^(1/4)-1} if x > 0 and f(x)=(e^(sin4x)-1)/(ln(1+tan2x)) if x < 0 Is it possible to difine f(0) to make the function continuous at x=0 . If yes what is.the value of f(0) , if not then indicate the nature of discontinuity.

If f(x)=log_(e)(log_(e)x)/log_(e)x then f'(x) at x = e is

L e t f(x)=(1-tanx)/(4x-pi),x!=pi/4,x in [0,pi/2], If f(x)i s continuous in [0,pi/4], then find the value of f(pi/4)dot

If int(tan^(9)x)dx=f(x)+log|cosx|, where f(x) is a polynomial of degree n in tan x, then the value of n is

Find the range of f(x)=(log)_e x-((log)_e x)^2/(|(log)_e x|)

lim_(xtoa) (log(x-a))/(log(e^(x)-e^(a)))

If f(x)=(log)_e((x^2+e)/(x^2+1)) , then the range of f(x)

"If "log_(e)(log_(e) x-log_(e)y)=e^(x^(2_(y)))(1-log_(e)x)," then find the value of "y'(e).

If f(x) = sin^(-1) (sin ("log"_(2) x)) , then find the value of f(300)